[Answer] How many atoms of aluminum are present in a sample that has a mass of 155.30 g?

Answer: 3.47 x 10^24

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How many atoms of aluminum are present in a sample that has a mass of 155.30 g? 5.756116 mol will contain : 5.756116*6.022*10^23 = 3.4663 * 10^24 atoms …. Start studying Molar Masses. Learn vocabulary terms and more with flashcards games and other study tools. ... How many atoms of aluminum are present in a sample that has a mass of 155.3 g …. Thu Mar 13 2014 · molar mass Al = 26.98g/mol . mol Al in 155.30g = 155.30/26.98 = 5.756116 mol Al . 1mo Al contains 6.022*10^23 Al atoms . 5.756116 mol will contain : 5.756116*6.022*10^23 = 3.4663 * 10^24 atoms - answer to 5 significant figures. How many atoms of aluminum are present in a sample that has a mass of 155 30 g ? The atomic weight of aluminum is 26.982 u how many ... The atomic weight of aluminum is 26.982 u how many ... Chemistry Chapter 4 Homework Chemistry Chapter 4 Homework The number of sodium ions is equal to the number of formula units of salt. How many atoms of aluminum are present in a sample that has a mass of 155.3 g? 3.47 x 10^24 . Which statement best describes … Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present or 4.01 E23 molecules. Each molecule of Al2S3...

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