ANSWERTRIVIA.COM: We ask you, humbly: don't scroll away.

Dear Reader, If you use ANSWERTRIVIA a lot, this message is for you. We're sure you are busy so we'll make this quick: Today we need your help. We don't have salespeople. We depend on donations from exceptional readers, but fewer than 2% give. If you donate just a coffee, lunch or whatever you can today, ANSWERTRIVIA could keep thriving. Thank you.
(Secure PayPal)
*Everything counts! No minimum threshold!
Thank you for inspiring us!

Enter Another Question

5/19/18

which of the following is the strongest reducing agent

We have looked all around the web to find the most relevant answer to your query: 


which of the following is the strongest reducing agent


  • ? A) F2 B)F- C)Li+ D)Li GIVEN TABLE ON OTHER SIDE THIS CARD. D since it on right ...

  • 23) ? A) Cl2+(aq) B) Cr3+( aq) C) Cl-(aq) D) Cr(s) E) Cl(s). D. 24) weakest ...

  • A an element (such as calcium) or compound that loses (or " donates") an electron to another chemical species in a redox chemical reaction. Since losing electrons, it said to have been oxidized. .... To tell , one can change sign its respective ...

If you can not able to find the answer following text may help you
  • one statements does not describe equilibrium state? ... species ? 1) Mn2+ 2) Mn
  • /are green house gas(es)? ..... substance oxidized in an oxidation reduction reaction serves as by losing electrons.
  • What occurs during operation a voltaic cell based on reaction ? ... according to spontaneous ...
  • According to table reduction potentials, ... species that most spontaneously ...
  • statements correctly describes this polarity? ... If ΔH = -50.0 kJ and ΔS = -0.300 kJ/K , reaction spontaneous below a certain temperature. .... in cycle acting as an oxidizing agent and respectively. .... molecules would be ?
  • oxidation state nitrogen in ammonium ion (NH41+) ______. -3. oxidation ... ? (If necessary  ...
  • agents accept electrons from oxidizing agents • All above are correct ... oxidizing ? • NADH • FMN


If you want to answer this question or elaborate it, just do it with below below format in comment box:

@Answer@YourDisplayName@ 

We will ensure your response will help others.

No comments:

Post a Comment