Answer: MN/MO
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Given right triangle MNO which represents the value of cos(M)?
In a right angle triangle cosine of any acute angle = Base/ Hypotenuse In the ∠ NMO Hypotenuse is MO and base of the triangle is MN. Therefore cos (M) = Base / Hypotenuse = MN / MO
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Triangle MNO is a right triangle. Recall the mnemonics CAH. The cosine ratio is the ratio of the length of the adjacent side to angle M and the length of the hypotenuse. That is This implies that
The cosine ratio is the ratio of the length of the adjacent side to angle M and the length of the hypotenuse. That is This implies that Given right triangle JKM which correctly describes the locations of the sides in relation to ∠J? a is the hypotenuse b is adjacent c is opposite Given right triangle MNO which represents the value of cos(M)?
The right angled triangle is MNO where N is the right angle. The image of the triangle showing these values is attached below: Let us use the formula of to determine the value of cos M. Hence where adjacent side = MN and hypotenuse = M...
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