[Answer] How many atoms of aluminum are present in a sample that has a mass of 155.30 g?

Answer: 3.47 x 10^24

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How many atoms of aluminum are present in a sample that has a mass of 155.30 g? Thu Mar 13 2014 · Best Answer: molar mass Al = 26.98g/mol. mol Al in 155.30g = 155.30/26.98 = 5.756116 mol Al. 1mo Al contains 6.022*10^23 Al atoms. 5.756116 mol will contain : 5.756116*6.022*10^23 = 3.4663 * 10^24 atoms … Start studying Molar Masses. Learn vocabulary terms and more with flashcards games and other study tools. ... How many atoms of aluminum are present in a sample that has a mass of 155.30 g … Start studying Percent Composition and Molecular Formula. Learn vocabulary terms and more with flashcards games and other study tools. ... How many atoms of aluminum are present in a sample that has a mass of 155.30 g ? 3.47 x 10^24. YOU MIGHT ALSO LIKE... Chemical Science Final … Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms … Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms so there are 8.02 E23 atoms of aluminum present. Which has a greater mass 4 x 1023 C atoms or 2 x 1023 S atom...

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