[Answer] How many atoms of aluminum are present in a sample that has a mass of 155.30 g?

Answer: 3.47 x 10^24

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How many atoms of aluminum are present in a sample that has a mass of 155.30 g? How many atoms of aluminum are present in a sample that has a mass of 155.30 g ? Thu Mar 13 2014 · Best Answer: molar mass Al = 26.98g/mol. mol Al in 155.30g = 155.30/26.98 = 5.756116 mol Al. 1mo Al contains 6.022*10^23 Al atoms. 5.756116 mol will contain : 5.756116*6.022*10^23 = 3.4663 * 10^24 atoms - answer to 5 significant figures. How many atoms of aluminum are present in a sample that has a mass of 155.30 g ? Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms … 1.02 * 10^(23)" atoms of Al" The key to this problem is the correct interpretation of what atomic weight means. Notice that aluminium is said to have an atomic mass of "26.982 u". The unit used here is the unified atomic mass unit u. The unified atomic mass unit is defined as 1/12"th" of the mass of a neutral carbon-12 atom and is approximately equal to the mass of one nucleon as in the mass ... The atomic weight of aluminum is 26.982 u how many ... Chemistry Chapter 4 Homework Chemistry Chapter 4 Homework The atomic weight of aluminum is 26.982 u how many ... Alumi...

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