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5/3/20

[Answer] If the molar mass of sodium nitrate (NaNO3) is calculated to be 85.00 g/mol how many formula units are present in 11.0 g of sodium nitrate?

Answer: 7.79 x 10^22




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If the molar mass of sodium nitrate (NaNO3) is calculated to be 85.00 g/mol how many formula units are present in 11.0 g of sodium nitrate? Start studying Molar Masses. Learn vocabulary terms and more with flashcards games and other study tools. ... If the molar mass of sodium nitrate (NaNO3) is calculated to be 85.00 g/mol how many formula units are present in 11.0 g of sodium nitrate ? 7.79 x 10^22. Sodium Nitrate NaNO3 Molar Mass Molecular Weight. • HNO3 + NaHCO3 = NaNO3 + CO2 + H2O • 4 Zn + 7 NaOH + NaNO3 = 4 Na2ZnO2 + NH3 + 2 H2O The underflow of each vat is heated before passing to the next one since the dissolution of sodium nitrate is endothermic. Sodium nitrate therefore dissolves preferentially. The product solution obtained after leaching contains 450 g /L of sodium nitrate and is cooled to 5 - 10 °C in heat exchangers and with ammonia refrigerating equipment. The molar mass of NaNO3 is 85.00 g/mol and if the 4.50 liter of 1.5 M (if this means moles) then the mass of NaNO3 should just be 85.0 x 1.5 = 127.5grams This appears to be the case since the concentration of the solution is already given at 1.5 moles if M = moles. ... Molar mass of sodium nitrate = 85.00 g/mol . This compound is also known as Sodium Nitrate . ... grams NaNO3 to moles ... Finding molar mass starts with units of grams per mole ( g/mol ). When calculating molecular weight of a chemical compound it tells us how many grams are in one mole of that substance. The formula weight is simply the weight in atomic mass units of all the atoms in a ... How many grams Sodium Nitrate in 1 mol ? The answer is...

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