[Answer] If the molar mass of sodium nitrate (NaNO3) is calculated to be 85.00 g/mol how many formula units are present in 11.0 g of sodium nitrate?

Answer: 7.79 x 10^22

Most relevant text from all around the web:

If the molar mass of sodium nitrate (NaNO3) is calculated to be 85.00 g/mol how many formula units are present in 11.0 g of sodium nitrate? If the molar mass of sodium nitrate (NaNO3) is calculated to be 85.00 g/mol how many formula units are present in 11.0 g of sodium nitrate ? 7.79 x 10^22 Avogadro's number was calculated by determining the number of atoms in Sodium Nitrate NaNO3 Molar Mass … The underflow of each vat is heated before passing to the next one since the dissolution of sodium nitrate is endothermic. Sodium nitrate therefore dissolves preferentially. The product solution obtained after leaching contains 450 g /L of sodium nitrate and is cooled to 5 - 10 °C in heat exchangers and with ammonia refrigerating equipment. Sodium Nitrate NaNO3 Molar Mass Molecular Weight. • HNO3 + NaHCO3 = NaNO3 + CO2 + H2O • 4 Zn + 7 NaOH + NaNO3 = 4 Na2ZnO2 + NH3 + 2 H2O The molar mass of NaNO3 is 85.00 g/mol and if the 4.50 liter of 1.5 M (if this means moles) then the mass of NaNO3 should just be 85.0 x 1.5 = 127.5grams This appears to be the case since the concentration of the solution is already given at 1.5 moles if M = moles. · Thu Dec 08 2011 The number of moles of NaNO3 is given as the molality and the number of moles of H2O can be found using the molar mass . 1 kg H2 O = 1000 g x...

Disclaimer: 

Our tool is still learning and trying its best to find the correct answer to your question. Now its your turn, "The more we share The more we have". Comment any other details to improve the description, we will update answer while you visit us next time...Kindly check our comments section, Sometimes our tool may wrong but not our users.

Are We Wrong To Think We're Right? Then Give Right Answer Below As Comment