[Answer] If the molar mass of sodium nitrate (NaNO3) is calculated to be 85.00 g/mol how many formula units are present in 11.0 g of sodium nitrate?

Answer: 7.79 x 10^22

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If the molar mass of sodium nitrate (NaNO3) is calculated to be 85.00 g/mol how many formula units are present in 11.0 g of sodium nitrate? Start studying Molar Masses. Learn vocabulary terms and more with flashcards games and other study tools. ... If the molar mass of sodium nitrate (NaNO3) is calculated to be 85.00 g/mol how many formula units are present in 11.0 g of sodium nitrate ? 7.79 x 10^22. Molar mass of NaNO3 = 84.99467 g/mol . Convert grams Sodium Nitrate to moles or moles Sodium Nitrate to grams. Molecular weight calculation: 22.989770 + 14.0067 + 15.9994*3. Percent composition by element. Similar chemical formulas. Note that all formulas are case-sensitive. Did you mean to find the molecular weight of one of these similar formulas? The underflow of each vat is heated before passing to the next one since the dissolution of sodium nitrate is endothermic. Sodium nitrate therefore dissolves preferentially. The product solution obtained after leaching contains 450 g /L of sodium nitrate and is cooled to 5 - 10 °C in heat exchangers and with ammonia refrigerating equipment. Sodium Nitrate NaNO3 Molar Mass Molecular Weight. • HNO3 + NaHCO3 = NaNO3 + CO2 + H2O • 4 Zn + 7 NaOH + NaNO3 = 4 Na2ZnO2 + NH3 + 2 H2O ...

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