Answer: 29 J
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The specific heat capacity of lead is 0.13 J/g-K. How much heat (in J) is required to raise the temperature of of lead from 22 °C to 37 °C?5.8 × 10-4 J-0.13 J0.13 J2.0 J29 J
Sat May 08 2010 · The specific heat capacity (cp) of lead is 0.13 J /g ° C . How much heat ( in J ) is required to raise the temperature of 15 grams of lead from 22 ° C to 37 ° C ? a. 2.0 b. - 0.13 c . 0.13 …
6) The specific heat capacity of lead is 0.13 J/g-K . How much heat ( in J ) is required to raise the temperature of 15 g of lead from 22degreeC to 37 degree C ?
Sun Oct 25 2009 · 37 ° C - 22 ° C = 15° C delta which is 15K delta also. So how do you get Joules from all this. If you multiply 0.13 J/g-K times 1.5g and 15K the grams cancel out and the Kelvins cancel out and you end up with 0.13 * 1.5 * 15 Joules
The specific heat capacity of lead is 0.13J/g-K. How much heat ( in J ) is required to raise the temperature of 15g of lead from 22C to 37C? ... A 25.5-g piece of cheddar cheese contains 37 % fat 28% protein and 4% carbohydrate. The respective fuel values for protein fat and carbohydrate are 17 38 and 17 kJ/g respectively. ...
The specific heat capacity of lead is 0.13 J /g° C . How much heat ( in J ) is required to raise the temperature of 15 g of lead from 22 ° C to 37 ° C ? A) 2.0 J B) - 0.13 J C) 5.8 × 10-4 J D) 29 J E) 0.13 J
The specific heat capacity of lead is 0.13 J /g°...
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