[Answer] The value of ΔH° for the reaction (which produces 4 mol NaOH) below is -126 kJ. ________ kJ are released when 2 mol of NaOH is formed in the reaction? 2Na2O2 (s) + 2H2O (l) → 4NaOH (s) + O2 (g)63-1267.82523.9

Answer: 63

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The value of ΔH° for the reaction (which produces 4 mol NaOH) below is -126 kJ. ________ kJ are released when 2 mol of NaOH is formed in the reaction? 2Na2O2 (s) + 2H2O (l) → 4NaOH (s) + O2 (g)63-1267.82523.9 Mon Nov 07 2011 · Well the reaction says you have 4 mol of NaOH so if you want to know what heat is when you have only HALF that number then 126 / 2 . Right? For the second one calculate the number of mol in 12 g of CO. mol = mass / Molar mass mol = 12 g / 28.01 = 0.4284 mol . Now ONE mol of CO would produce 482 / 2 or 241 kJ Tue Nov 30 2010 · The value of ΔH ° for the reaction below is - 126 kJ . The amount of heat that is released by the reaction of 25.0 g of Na2O2 with water is __________ kJ . 2Na2O2 ( s ) + 2H2O ( l ) → 4NaOH ( s ) + O2 ( g ) A) 20. 2 B) 40. 4 C) 67.5 D) 80.8 E) - 126 Mon Apr 20 2015 · The value of ΔH ° for the reaction below is -790 kJ . The enthalpy change accompanying the reaction of 0.95 g of S is _____ kJ . 2S ( s ) + 3O2 ( g ) ---> 2SO3 ( g ) Question 15 options: 23 -23 … Fri Feb 25 2011 · 2 . Determine heat produced. Note: When 2 moles of C6H6 react 6535 kJ of heat is released . (from reaction ) 0.205 moles C6H6 x (-6535 kJ / 2 moles C6H6) = -669 kJ . 669 kJ of heat is released . That' s it!n_n 4 ) The value of ΔH ° for the reaction below is - 126 kJ . _____...

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