Answer: (2x)5 - 15(2x)4 + 90(2x)3 - 270(2x)2 + 405(2x) - 243 A
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What is the binomial expansion of (2x - 3)5?
11/03/2017. Mathematics. College. answer. answered. What is the binomial expansion of (2x – 3)5? a) (2x )5 – 15 (2x)4 + 90 (2x)3 – 270 (2x)2 + 405 (2x) – 243. d) (2x)5 + 15 (2x)4 – 90 (2x)3 + 270 (2x)2 – 405 (2x) + 243. c) (2x)5 + 15 (2x)4 + 90 (2x)3 + 270 (2x)2 + 405 (2x) + 243.
Find an answer to your question What is the binomial expansion of (2x-3)^5 jasminer257 jasminer257 02/04/2019 Mathematics Middle School What is the binomial expansion of (2x-3)^5 2 See answers choixongdong choixongdong Answer: (2x)^ 5 - 15(2x)^4 + 90(2x)^ 3 - 270(2x)^2 + 405(2x) - 243. first option. Step-by-step explanation: Exponent is 5 so the ...
Therefore the binomial expansion of the given expression is {eq}\displaystyle \boxed{\color{blue} { (2x - 3y)^ 5 = 32x^ 5 -240x^4y+720x^3y^2-1080x^2y^ 3 +810xy^4-243y^ 5 }} {/eq} Become a member and ...
Sep 12 2014 · You can also calculate the coefficients using Pascal's Triangle. Typically you don't want to use Pascal's Triangle for binomial expansions above 10 for the exponent or when calculating a single term of an expansion such as calculating the 8th term of the binomial expansion of (2x + 3 )^23. 245157*2^16* 3 ^7*x^16 where 245157 = 23 choose 7
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