[Answer] What are the solutions of the equation x4 - 5x2 - 36 = 0? Use factoring to solve.

Answer: x = ±2i and x = ±3B

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What are the solutions of the equation x4 - 5x2 - 36 = 0? Use factoring to solve. Mon Jun 23 2003 · 2) Use variable change z = x + m/x. The general case along Ferrari's lines. To begin the quartic must first be converted to a depressed quartic. Converting to a depressed quartic. Let + + + + = (′) be the general quartic equation which it is desired to solve . A quadratic equation with real or complex coefficients has two solutions called roots.These two solutions may or may not be distinct and they may or may not be real. Factoring by inspection. It may be possible to express a quadratic equation ax 2 + bx + c = 0 as a product (px + q)(rx + s) = 0 .In some cases it is possible by simple inspection to determine values of p q r and s … This is the resolvent cubic of the quartic equation . The value of m may thus be obtained from Cardano's formula.When m is a root of this equation the right-hand side of equation is the square (−).However this induces a division by zero if m = 0 .This implies q = 0 and thus that...

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